Home
Class 14
MATHS
sqrt(8281)=?...

`sqrt(8281)=?`

A

89

B

97

C

93

D

91

Text Solution

AI Generated Solution

The correct Answer is:
To find the square root of 8281 using the long division method, we can follow these steps: ### Step 1: Pair the digits Start from the right and pair the digits of the number. For 8281, we can pair it as (82)(81). ### Step 2: Find the largest square Look for the largest square number less than or equal to the first pair (82). The largest square is 9^2 = 81. ### Step 3: Write down the quotient Write down 9 as the first digit of the quotient. ### Step 4: Subtract and bring down the next pair Subtract 81 from 82, which gives us 1. Now, bring down the next pair (81) next to the remainder (1), making it 181. ### Step 5: Double the quotient Double the current quotient (which is 9) to get 18. ### Step 6: Find the next digit Now, we need to find a digit (let's call it x) such that (180 + x) * x is less than or equal to 181. Testing x = 1: - (180 + 1) * 1 = 181, which is equal to 181. ### Step 7: Write down the next digit So, we write down 1 next to the quotient, making it 91. ### Step 8: Subtract again Subtract 181 from 181, which gives us 0. ### Step 9: Conclusion Since there are no more digits to bring down and the remainder is 0, we conclude that the square root of 8281 is 91. Thus, we have: \[ \sqrt{8281} = 91 \]

To find the square root of 8281 using the long division method, we can follow these steps: ### Step 1: Pair the digits Start from the right and pair the digits of the number. For 8281, we can pair it as (82)(81). ### Step 2: Find the largest square Look for the largest square number less than or equal to the first pair (82). The largest square is 9^2 = 81. ...
Promotional Banner

Topper's Solved these Questions

  • SIMPLE INTEREST AND COMPOUND INTEREST

    IBPS & SBI PREVIOUS YEAR PAPER|Exercise MCQs|78 Videos
  • TIME , SPEED & DISTANCE (BOAT & STREAM)

    IBPS & SBI PREVIOUS YEAR PAPER|Exercise Question|91 Videos

Similar Questions

Explore conceptually related problems

(1)/(sqrt(9)-sqrt(8))-(1)/(sqrt(8)-sqrt(7))+(1)/(sqrt(7)-sqrt(6))-(1)/(sqrt(6)-sqrt(5))+(1)/(sqrt(5)-sqrt(4))=?

(1)/(1+sqrt(2))+(1)/(sqrt(2)+sqrt(3))+(1)/(sqrt(3)+sqrt(4))+(1)/(sqrt(4)+sqrt(5))+(1)/(sqrt(5)+sqrt(6))+(1)/(sqrt(6)+sqrt(7))+(1)/(sqrt(7)+sqrt(8))+(1)/(sqrt(8)+sqrt(9))

(1)/(1+sqrt(2))+(1)/(sqrt(2)+sqrt(3))+(1)/(sqrt(3)+sqrt(4))+(1)/(sqrt(4)+sqrt(5))+(1)/(sqrt(5)+sqrt(6))+(1)/(sqrt(6)+sqrt(7))+(1)/(sqrt(7)+sqrt(8))+(1)/(sqrt(8)+sqrt(8))

sqrt(11)+sqrt(3),sqrt(20),sqrt(5)sqrt(15)+sqrt(22),sqrt(25),sqrt(10)3+sqrt(55),sqrt(15),sqrt(25)]|=

Evaluate : (sqrt(7)+sqrt(5))/(sqrt(7)+sqrt(20)+sqrt(28)-sqrt(5)-sqrt(80))

sqrt(2+sqrt(2+sqrt(2+sqrt(2+sqrt(2)))))=