Home
Class 14
MATHS
(5)/(6)div(6)/(7)xx?-(8)/(9)div1(3)/(5)+...

`(5)/(6)div(6)/(7)xx?-(8)/(9)div1(3)/(5)+(3)/(4)xx3(1)/(3)=2(7)/(9)`

A

`7/6`

B

`6/7`

C

1

D

`6/9`

Text Solution

AI Generated Solution

The correct Answer is:
To solve the equation \[ \frac{5}{6} \div \frac{6}{7} \times ? - \frac{8}{9} \div 1 \frac{3}{5} + \frac{3}{4} \times 3 \frac{1}{3} = 2 \frac{7}{9} \] we will follow these steps: ### Step 1: Convert Mixed Numbers to Improper Fractions First, we convert the mixed numbers to improper fractions. - \(1 \frac{3}{5} = \frac{5 \times 1 + 3}{5} = \frac{8}{5}\) - \(3 \frac{1}{3} = \frac{3 \times 3 + 1}{3} = \frac{10}{3}\) - \(2 \frac{7}{9} = \frac{2 \times 9 + 7}{9} = \frac{25}{9}\) Now, the equation looks like this: \[ \frac{5}{6} \div \frac{6}{7} \times ? - \frac{8}{9} \div \frac{8}{5} + \frac{3}{4} \times \frac{10}{3} = \frac{25}{9} \] ### Step 2: Simplify Each Term Now, we simplify each term in the equation. 1. **First Term:** \[ \frac{5}{6} \div \frac{6}{7} = \frac{5}{6} \times \frac{7}{6} = \frac{5 \times 7}{6 \times 6} = \frac{35}{36} \] 2. **Second Term:** \[ \frac{8}{9} \div \frac{8}{5} = \frac{8}{9} \times \frac{5}{8} = \frac{5}{9} \] 3. **Third Term:** \[ \frac{3}{4} \times \frac{10}{3} = \frac{3 \times 10}{4 \times 3} = \frac{10}{4} = \frac{5}{2} \] Now, substituting these back into the equation gives: \[ \frac{35}{36} \times ? - \frac{5}{9} + \frac{5}{2} = \frac{25}{9} \] ### Step 3: Combine Like Terms Next, we need to combine the constants on the left side: \[ \frac{5}{2} - \frac{5}{9} \] To combine these, we find a common denominator, which is 18: \[ \frac{5}{2} = \frac{5 \times 9}{2 \times 9} = \frac{45}{18} \] \[ \frac{5}{9} = \frac{5 \times 2}{9 \times 2} = \frac{10}{18} \] Now, we can subtract: \[ \frac{45}{18} - \frac{10}{18} = \frac{35}{18} \] So the equation now looks like: \[ \frac{35}{36} \times ? + \frac{35}{18} = \frac{25}{9} \] ### Step 4: Isolate the Variable Now, isolate the term with the question mark: \[ \frac{35}{36} \times ? = \frac{25}{9} - \frac{35}{18} \] To subtract these fractions, we need a common denominator, which is 18: \[ \frac{25}{9} = \frac{25 \times 2}{9 \times 2} = \frac{50}{18} \] Now we can subtract: \[ \frac{50}{18} - \frac{35}{18} = \frac{15}{18} = \frac{5}{6} \] So we have: \[ \frac{35}{36} \times ? = \frac{5}{6} \] ### Step 5: Solve for the Question Mark Now, multiply both sides by the reciprocal of \(\frac{35}{36}\): \[ ? = \frac{5}{6} \times \frac{36}{35} \] Calculating this gives: \[ ? = \frac{5 \times 36}{6 \times 35} = \frac{30}{35} = \frac{6}{7} \] Thus, the value of the question mark is: \[ \boxed{\frac{6}{7}} \]

To solve the equation \[ \frac{5}{6} \div \frac{6}{7} \times ? - \frac{8}{9} \div 1 \frac{3}{5} + \frac{3}{4} \times 3 \frac{1}{3} = 2 \frac{7}{9} \] we will follow these steps: ...
Promotional Banner

Topper's Solved these Questions

  • SIMPLE INTEREST AND COMPOUND INTEREST

    IBPS & SBI PREVIOUS YEAR PAPER|Exercise MCQs|78 Videos
  • TIME , SPEED & DISTANCE (BOAT & STREAM)

    IBPS & SBI PREVIOUS YEAR PAPER|Exercise Question|91 Videos

Similar Questions

Explore conceptually related problems

(5)/(6)-:(6)/(7)xx?-(8)/(9)-:1(3)/(5)+(3)/(4)xx3(1)/(3)=2(7)/(9)(7)/(6)(b)(6)/(7)(c)1(d) None of these

(5)/(6) -: (6)/(7) xx ? - (8)/(9) -: 1 (2)/(5) -: (3)/(4) xx 3 (1)/(3) = 2(7)/(9)

( (5)/(6)-:(6)/(7)times(6)/(7)-(8)/(9)-:1(3)/(5)+(3)/(4)times3(1)/(3)

(2)/(7)div(4)/(5)xx(7)/(9)xx9div5=?

(3)/(7)xx(9)/(14) div (5)/(7)=?

The value of (2(6)/(7)"of"4(1)/(5)div(2)/(3))xx1(1)/(9)div((3)/(2)xx2(2)/(3)"of"(1)/(2)div(1)/(4)) is :

(3)/(7) div (9)/(14)xx(6)/(11)=?

(5)/(8)xx2(3)/(5) div (4)/(9)=?

The value ok ((1(1)/(9) xx 1 (1)/(20) div (21)/(38)-(1)/(3))div(2 (4)/(9)div 1(7)/(15) of ""(3)/(5)))/((1)/(5) of (1)/(5) div (1)/(125) - (1)/(125) div (1)/(5) of"" (1)/(5)) lies between......