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1.5xx0.025+(?)^(2)=0.1...

`1.5xx0.025+(?)^(2)=0.1`

A

0.28

B

0.27

C

0.25

D

0.235

Text Solution

Verified by Experts

The correct Answer is:
C
`1.5xx0.025+(?)^(2)=0.1 rArr (?)^(2)=0.1-1.5xx0.025`
`rArr (?)^(2)=0.1-0.0375 rArr ?=sqrt(.0625)=0.25`
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