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What is the rate of interest at which Bi...

What is the rate of interest at which Binod has invested money?
A. The compound interest at this rate of Rs.2500 in 2 yrs is equal to the simple interest in 3 yrs of Rs. 5150 at the same rate.
B. The total simple interest on an investment of Rs. 12000 for 3 yrs and Rs. 10000 for 5 yrs at this rate is R. 5160
C. In 3 yrs Rs. 1500 at the same rate becomes Rs. 1725 by simple interest.

A

Any of them

B

A and either B or C

C

Only C

D

Only A and either B or C

Text Solution

AI Generated Solution

The correct Answer is:
To find the rate of interest at which Binod has invested money, we will analyze each statement (A, B, and C) provided in the question step by step. ### Step 1: Analyze Statement A **Statement A:** The compound interest at this rate of Rs. 2500 in 2 years is equal to the simple interest in 3 years of Rs. 5150 at the same rate. 1. **Compound Interest Formula:** \[ A = P(1 + \frac{R}{100})^T \] where \( A \) is the amount after time \( T \), \( P \) is the principal, \( R \) is the rate of interest, and \( T \) is the time in years. For \( P = 2500 \) and \( T = 2 \): \[ A = 2500(1 + \frac{R}{100})^2 \] The compound interest (CI) will be: \[ CI = A - P = 2500(1 + \frac{R}{100})^2 - 2500 \] 2. **Simple Interest Formula:** \[ SI = \frac{P \times R \times T}{100} \] For \( P = 5150 \) and \( T = 3 \): \[ SI = \frac{5150 \times R \times 3}{100} \] 3. **Setting the two interests equal:** \[ 2500(1 + \frac{R}{100})^2 - 2500 = \frac{5150 \times R \times 3}{100} \] This gives us one equation with one unknown \( R \). ### Step 2: Analyze Statement B **Statement B:** The total simple interest on an investment of Rs. 12000 for 3 years and Rs. 10000 for 5 years at this rate is Rs. 5160. 1. **Calculate Simple Interest for both investments:** - For Rs. 12000 for 3 years: \[ SI_1 = \frac{12000 \times R \times 3}{100} \] - For Rs. 10000 for 5 years: \[ SI_2 = \frac{10000 \times R \times 5}{100} \] 2. **Setting the total simple interest equal to Rs. 5160:** \[ SI_1 + SI_2 = 5160 \] \[ \frac{12000 \times R \times 3}{100} + \frac{10000 \times R \times 5}{100} = 5160 \] This also gives us one equation with one unknown \( R \). ### Step 3: Analyze Statement C **Statement C:** In 3 years, Rs. 1500 at the same rate becomes Rs. 1725 by simple interest. 1. **Calculate the Simple Interest:** \[ SI = A - P = 1725 - 1500 = 225 \] Using the simple interest formula: \[ 225 = \frac{1500 \times R \times 3}{100} \] 2. **Rearranging to find \( R \):** \[ R = \frac{225 \times 100}{1500 \times 3} \] This gives us a direct calculation for \( R \). ### Conclusion From the analysis of each statement: - **Statement A** provides an equation to find \( R \). - **Statement B** also provides an equation to find \( R \). - **Statement C** directly allows us to calculate \( R \). Thus, any of the statements A, B, or C is sufficient to determine the rate of interest. ### Final Answer The answer is that any of the statements A, B, or C is sufficient to find the rate of interest. ---

To find the rate of interest at which Binod has invested money, we will analyze each statement (A, B, and C) provided in the question step by step. ### Step 1: Analyze Statement A **Statement A:** The compound interest at this rate of Rs. 2500 in 2 years is equal to the simple interest in 3 years of Rs. 5150 at the same rate. 1. **Compound Interest Formula:** \[ A = P(1 + \frac{R}{100})^T ...
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