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Quantity I: Unit digit of the number [(4...

Quantity I: Unit digit of the number `[(4653)^(25)]^(27)`
Quantity II: Unit digit of the number `[(257)^(23)]^(22)`

A

Quantity I `gt` Quantity II

B

Quantity I `lt` Quantity II

C

Quantity I `ge` Quantity II

D

Quantity I `le` Quantity II

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The correct Answer is:
To solve the problem, we need to find the unit digits of two quantities and then compare them. ### Step 1: Find the unit digit of Quantity I: \([(4653)^{25}]^{27}\) 1. **Identify the unit digit of the base**: The unit digit of 4653 is 3. 2. **Simplify the expression**: We need to find the unit digit of \(3^{(25 \times 27)}\). 3. **Calculate the exponent**: \[ 25 \times 27 = 675 \] 4. **Find the unit digit of \(3^{675}\)**: - The unit digits of powers of 3 follow a pattern: - \(3^1 = 3\) (unit digit is 3) - \(3^2 = 9\) (unit digit is 9) - \(3^3 = 27\) (unit digit is 7) - \(3^4 = 81\) (unit digit is 1) - This pattern (3, 9, 7, 1) repeats every 4 terms. 5. **Determine the position in the cycle**: - Calculate \(675 \mod 4\): \[ 675 \div 4 = 168 \quad \text{(remainder 3)} \] - The remainder is 3, which corresponds to the unit digit of \(3^3\), which is 7. 6. **Conclusion for Quantity I**: The unit digit of \([(4653)^{25}]^{27}\) is **7**. ### Step 2: Find the unit digit of Quantity II: \([(257)^{23}]^{22}\) 1. **Identify the unit digit of the base**: The unit digit of 257 is 7. 2. **Simplify the expression**: We need to find the unit digit of \(7^{(23 \times 22)}\). 3. **Calculate the exponent**: \[ 23 \times 22 = 506 \] 4. **Find the unit digit of \(7^{506}\)**: - The unit digits of powers of 7 follow a pattern: - \(7^1 = 7\) (unit digit is 7) - \(7^2 = 49\) (unit digit is 9) - \(7^3 = 343\) (unit digit is 3) - \(7^4 = 2401\) (unit digit is 1) - This pattern (7, 9, 3, 1) repeats every 4 terms. 5. **Determine the position in the cycle**: - Calculate \(506 \mod 4\): \[ 506 \div 4 = 126 \quad \text{(remainder 2)} \] - The remainder is 2, which corresponds to the unit digit of \(7^2\), which is 9. 6. **Conclusion for Quantity II**: The unit digit of \([(257)^{23}]^{22}\) is **9**. ### Step 3: Compare the two quantities - Quantity I: Unit digit is **7**. - Quantity II: Unit digit is **9**. ### Final Conclusion: Quantity I is smaller than Quantity II.

To solve the problem, we need to find the unit digits of two quantities and then compare them. ### Step 1: Find the unit digit of Quantity I: \([(4653)^{25}]^{27}\) 1. **Identify the unit digit of the base**: The unit digit of 4653 is 3. 2. **Simplify the expression**: We need to find the unit digit of \(3^{(25 \times 27)}\). 3. **Calculate the exponent**: \[ ...
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