A. vessel contains 5 litres of Liquid A and 20 litres of Liquid
B. `20%` of the contents of the vessel are removed. To the remaining contents, x litres of Liquid A is added to reverse the ratio of Liquid A and Liquid B. Then y litres of Liquid B is added again to reverse the ratio of Liquid A and Liquid B.
Quantity I: Value of 'y'
Quantity II: Value of 'x' (a) Quantity I = Quantity II or No relation (b) Quantity I ≤ Quantity II (c) Quantity I ≥ Quantity II (d) Quantity I > Quantity II

Options

A. Quantity `I=` Quantity II or No relation
B. Quantity `I le` Quantity II
C. Quantity `I ge` Quantity II
D. Quantity `Igt` Quantity II

Explanation

To solve the problem step by step, let's break down the information given and calculate the required values for \( x \) and \( y \).

### Step 1: Initial Setup
- The vessel contains:
- Liquid A: 5 liters
- Liquid B: 20 liters
- Total liquid in the vessel = 5 liters + 20 liters = 25 liters

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