Quantity I: 'x': A pipe alone can fill a cistern in 60 minutes. But due to leakage pipe filled only `80%` of the cistern in 1 hour. 'x' is the capacity of cistern in litres of due to leakage 60 liter can be leaked out in 1 hour.
Quantity II: 250 liters

Options

A. Quantity `Igt` Quantity II
B. Quantity `I lt` Quantity II
C. Quantity `I ge` Quantity II
D. Quantity `I =` Quantity II

Explanation

To solve the problem, we need to determine the capacity of the cistern (Quantity I, denoted as 'x') based on the information provided about the pipe and the leakage. Let's break down the solution step by step.

### Step 1: Understand the filling capacity of the pipe
The problem states that a pipe can fill a cistern in 60 minutes. This means that the filling rate of the pipe is:
- **Filling Rate of Pipe = 1 cistern / 60 minutes = 1/60 cisterns per minute.**

### Step 2: Determine the amount filled in one hour
In one hour (60 minutes), the pipe would theoretically fill:
- **Amount filled in one hour = (1/60 cisterns per minute) * 60 minutes = 1 cistern.**

However, due to leakage, the pipe only fills 80% of the cistern in one hour.

### Step 3: Calculate the actual amount filled due to leakage
Since the pipe fills only 80% of the cistern in one hour, we can express this as:
- **Amount filled due to leakage = 0.8 * 1 cistern = 0.8 cisterns.**

### Step 4: Relate the leakage to the amount filled
The problem states that due to leakage, 60 liters can be leaked out in one hour. This means that the leakage accounts for 20% of the total capacity of the cistern:
- **Leakage = 20% of total capacity (x) = 60 liters.**

### Step 5: Calculate the total capacity of the cistern
To find the total capacity (x) of the cistern, we can set up the equation:
- **0.2x = 60 liters.**

Now, solve for x:
- **x = 60 liters / 0.2 = 300 liters.**

### Step 6: Compare Quantity I and Quantity II
Now we have determined that:
- **Quantity I (x) = 300 liters.**
- **Quantity II = 250 liters.**

### Conclusion
Since 300 liters (Quantity I) is greater than 250 liters (Quantity II), we conclude that:
- **Quantity I > Quantity II.**

### Final Answer
The answer is **Option 1**: Quantity I is greater than Quantity II.

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