Quantity I: 'x': Area of a square is 361 `cm^(2)` whose perimeter is equal to perimeter of a rectangle. Length of rectangle is 4cm more than breadth of reactagle. Length of reactangle is 4cm more than breadth of rectangle. 'x' is the area of reactangle
Quantity II: 375 `cm^(2)`

Options

A. Quantity `Igt` Quantity II
B. Quantity `I lt` Quantity II
C. Quantity `I ge` Quantity II
D. Quantity `I le` Quantity II

Explanation

Quantity I:
Side of square `=sqrt(361)=19` cm
Let length of rectangle be x and breadth of rectangle be `(x-4)` cm
ATQ
`(x+x-4)=(4xx19)/(2)=38`
`x=21`
area of rectangle `=21xx17=357 cm^(2)`
Quantity II: `357cm^(2)`
Quantity i = Quantity II