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Quantity I: 'x':x^(2)+x-12=0 Quantity ...

Quantity I: `'x':x^(2)+x-12=0`
Quantity II. `'y' :y^(2)+7y+10=0`

A

Quantity `Igt` Quantity II

B

Quantity `I lt` Quantity II

C

Quantity `I ge` Quantity II

D

Quantity `I le` Quantity II

Text Solution

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Quantity I. `x^(2)+x-12=0`
`x^(2)+4x-3x-12=0`
`x(x+4)-3(x+4)=0`
`(x-3)(x+4)=0`
`x=3.-4`
Quantity II. `y^(2)+7y+10=0`
`y^(2)+2y+5y+10=0`
`y(y+2)+5(y+2)=0`
`(y+2)(y+5)=0`
`y=-5,-2`
No relation
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