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If A=[[1, 1, 1],[ 1, 1, 1],[ 1, 1, 1]], ...

If `A=[[1, 1, 1],[ 1, 1, 1],[ 1, 1, 1]]`, prove that `A^n=[[3^(n-1),3^(n-1),3^(n-1)],[3^(n-1),3^(n-1),3^(n-1)],[3^(n-1),3^(n-1),3^(n-1)]], n in N.`

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