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Charge required to liberated 11.5 g sodi...

Charge required to liberated `11.5 g` sodium is .

A

0.5F

B

0.1F

C

1.5F

D

96500 colombs

Text Solution

Verified by Experts

The correct Answer is:
A
`Na^(+)+e^(-)toNa`
Charge (in F)=moles of `e^(-)` used=moles of Na deposited
`=(11.5)/(23)gm=0.5` faraday.
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