What is the amount of chlorine evoled when `2` amperes of current is passed for `30` minumtes in an aqueous solution of `NaCI` ?

Options

A. 66g
B. 1.32g
C. 33g
D. 99g

Answer

B

Explanation

At anode `Cl^(-)to(1)/(2)Cl_(2)+e^(-)`
`E_(Cl_(2))=(35.5xx2)/(2)=35.5`
`W_(Cl_(2))=(E_(Cl_(2))xxIxxt)/(96500)=(35.5xx2xx30xx60)/(96500)=1.32gm`