Two electrolytic cells, one containing acidified ferrous sulphate and another acidified ferric chloride, are in series. The ratio of masses of Iron deposited at the cathode in the two cells will be

Options

A. `3:1`
B. `2:`
C. `1:1`
D. `3:2 `

Answer

D

Explanation

At cathode:
`Fe^(2+)+2e^(-)toFe,Fe^(3+)+3e^(-)toFe`
`(E_(Fe))=("Atomic.weight")/(2),(E_(Fe))_(2)=("Atomic.weight")/(3)`
Ratio of weight of Fe liberated
`=("Atomic weight")/(3):("Atomic weight")/(2)=3:2`