A current is passed through two cells connected in series. The first cell contains `X(NO_(3))_(3(aq))` and the second cell contains `Y(NO_(3))_(2(aq))` . The relative atomic masses of X and Y are in the ratio `1:2`. What is the ratio of liberated mass of X to that of Y ?

Options

A. `3:2`
B. `1:2`
C. `1:3`
D. `3:1`

Answer

C

Explanation

The oxidation states of X and Y are `X^(3+) and Y^(2+)` given atomic masses are in the ratio of 1:2
`therefore` Equivalent masses are in the ratio
`(1)/(3):(2)/(2)` or `(1)/(3):1` or `1:3`