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A current of strength 2.5 amp was passed...

A current of strength 2.5 amp was passed through `CuSO_(4)` solution for 6 minutes 26 seconds. The amount of copper deposited is:-
(Atomic weight of `Cu=63.5`)
(1 faraday=96500 coulombs)

A

0.3175 g

B

3.175 g

C

0.635 g

D

6.35 g

Text Solution

Verified by Experts

The correct Answer is:
A
`Q=2.5xx386=96500C`
`2F(2xx96500C)` deposited `C u=63.5g`
`therefore`Hence 965 C will deposited, Cu=0.3175gm.
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