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The number of electrons passing per seco...

The number of electrons passing per second through a cross-section of copper wire carrying `10^(-6)` ampere:

A

`1.6xx10^(-19)`

B

`6xx10^(-35)`

C

`6xx10^(-16)`

D

`6xx10^(12)`

Text Solution

Verified by Experts

The correct Answer is:
D
Charge (coulombs) pass per second=`10^(-6)`
Number of electrons passed per second
`=(10^(-6))/(1.602xx10^(-19))=6.24xx10^(12)`
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