When 1 F of electricity is passed through acidulated water `O_(2)` evolved is

Options

A. 11.2 `dm^(3)`
B. 5.6 `dm^(3)`
C. 22.4 `dm^(3)`
D. 1.0 `dm^(3)`

Answer

B

Explanation

Reaction for electrolysis of water is:
`2H_(2)Oto4H^(+)+2O^(2-)`
Reaction for electrolysis of water is
`2H_(2)Oto4H^(+)+2O^(2-)`
`2O^(-)toO_(2)+4e^(-)`
`4e^(-)+4H^(+)to2H_(2)`
`becausen=4` so 4 faraday charge will leberate
1 mole=22.4 `dm^(3)` oxygen.
`therefore1` faraday charge will liberate `(22.4)/(4)=5.6dm^(3)O_(2)`.