The volume of `H_(2)` gas at NTP obtained by passing 4 amperes through acidified `H_(2)O` for 30 minutes is

Options

A. 0.0836L
B. 0.0432L
C. 0.1672L
D. 0.836L

Answer

D

Explanation

`H_(2)OtoH_(2)+(1)/(2)O_(2)`
`2H^(+)+2e^(-)toH_(2)`
For the production of one mole `H_(2)`,2 mole electrons (i.e., 2F charge) is required
`therefore`2 faraday`=2xx96500` coulomb charge liberate
`H_(2)=22400mL` at NTP.
`therefore4xx30xx60` coulomb charge will liberate
`H_(2)=(4xx30xx60xx22400)/(2xx96500)=835.6 ml`
`=0.836` l