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The equivalent conductance of 1 M benzoi...

The equivalent conductance of `1 M` benzoic acid is `12.8 ohm^(-1) cm^(2)`. If the conductance of benzoate ion and `H^(+)` ion are `12` and `288.42 ohm^(-1) cm^(2)` respectively. Its degree of dissociation is :

A

0.39

B

`3.9%`

C

0.0035

D

`0.039%`

Text Solution

Verified by Experts

The correct Answer is:
B
`wedge_(m_(C_(6)H_(5)COOH))^(@)=wedge_((C_(6)H_(5)COO^(-)))^(@)+wedge_((H^(+)))^(@)`
`=42+288.42=330.42`
`alpha=(wedge_(m)^(@))/(wedge_(m)^(@))=(12.8)/(330.42)=3.9%`
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