At `25^(@)C`, the molar conductances at infinite dilution for the strong electrolytes `NaOH, NaCl " and " BaCl_(2) " are " 248 xx 10^(-4), 126 xx 10^(-4)" and " 280 xx 10^(-4) S m^(2) mol^(-1)` respectively. `Lamda_(m)^(@) Ba (OH)_(2) " in " S m^(2) mol^(-1)`

Options

A. `52.4xx10^(-4)`
B. `524xx10^(-4)`
C. `402xx10^(-4)`
D. `262xx10^(-4)`

Answer

B

Explanation

`lamda_(Na^(+))^(@)+lamda_(OH^(-))^(@)=248xx10^(-4)Sm^(2)mol^(-1)`
`lamda_(Na^(+))^(@)+lamda_(Cl^(-))^(@)=126xx10^(-4)Sm^(2)mol^(-1)`
`lamda_(Ba^(2+))^(@)+lamda_(2Cl^(-))^(@)=280xx10^(-4)`
Now, `lamda_(Ba(OH)_(2))^(@)=lamda_(BaCl_(2))^(@)+2lamda_(NaOH)^(@)+2lamda_(NaCl)^(@)`
`lamda_(Ba(OH)_(2))^(@)=280xx10^(-4)+2xx248xx10^(-4)+2xx126xx10^(-4)`
`lamda_(Ba(OH)_(2))^(@)=524xx10^(-4)Sm^(2)mol^(-1)`.