Given `l//a=0.5 cm^(-1), R= 50 "ohm", N= 1.0.` The equivalent conductance of the electrolytic cell is .

Options

A. 10 `ohm^(-1)cm^(2)gmeq^(-1)`
B. 20 `ohm^(-1)cm^(2)gmeq^(-1)`
C. 300 ohm S `cm^(2)eq^(-1)`
D. 135.9S `cm^(2)eq^(-1)`

Answer

A

Explanation

`1//a=0.5cm^(-1),R=50ohm`
`p=(Ra)/(I)=(50)/(0.5)=100`
`wedge=kxx(1000)/(N)=(1)/(p)xx(1000)/(N)=(1)/(100)0xx(1000)/(1)`
`=10ohm^(-1)cm^(2)gm" "eq^(-1)`.