If the half-cell reaction `A+e^(-)toA^(-)` has a large negative reduction potentials, it follows that:

Options

A. A is readily reduced
B. A is readily oxidised
C. `A^(-)` is readily reduced
D. `A^(-)` is readily oxidised

Answer

D

Explanation

Since `E_(A//A^(-))^(@)` has large negative value, the tendency of A to be reduced to `A^(-)` is very small. In other words tendency of `A^-` to be oxidized to A is very large.