Anode reaction of a fuel cell is:-

Options

A. `Zn(Hg)+2OH^(-)toZnO_((s))+H_(2)O+2e^(-)`
B. `Pb_((s))+SO_(4(aq))^(2-)toPbSO_(4(s))+2e^(-)`
C. `2H_(2(g))+4OH_((aq))^(-)to4H_(2)O_((l))+4e^(-)`
D. `2Fe_((s))to2Fe^(2+)+4e^(-)`

Answer

To determine the anode reaction of a fuel cell, we need to understand the basic operation of a fuel cell and the specific reactions that occur at the anode.

### Step-by-Step Solution:

1. **Understanding Fuel Cells**: A fuel cell is an electrochemical cell that converts the chemical energy of a fuel (usually hydrogen) directly into electricity through a chemical reaction with an oxidizing agent (usually oxygen).

2. **Identifying the Anode**: In a fuel cell, the anode is the electrode where oxidation occurs. This is the site where the fuel (hydrogen) is supplied.

3. **Anode Reaction**: At the anode of a hydrogen fuel cell, hydrogen gas (H₂) is oxidized. The reaction can be written as:
\[ \text{H}_2 \rightarrow 2\text{H}^+ + 2e^- \]
Here, hydrogen gas (H₂) loses electrons (is oxidized) to form protons (H⁺ ions).

4. **Electrons Flow**: The electrons released during the oxidation process flow through an external circuit, generating electric current.

5. **Summary of the Reaction**: Thus, the complete anode reaction in a hydrogen fuel cell can be summarized as:
\[ \text{Anode Reaction: } \text{H}_2 \rightarrow 2\text{H}^+ + 2e^- \]