A conductivity cell has been calibrated with a 0.01 M 1:1 electrolyte solution (specific conductance, `k=1.25xx10^(-3)S" "cm^(-1)`) in the cell and the measured resistance was 800 ohms at `25^(@)C`. The constant will be

Options

A. 1.02 cm
B. 0.102 `cm^(-1)`
C. 1.00 `cm^(-1)`
D. 0.5 `cm^(-1)`

Answer

C

Explanation

`K=1.25xx10^(-3)S" "cm^(-1):rho=(1)/(K)=(1)/(1.25xx10^(-3))`
`R=rho(l)/(A)`
`therefore800=(1)/(1.25xx10^(-3))xx((l)/(A))`, where `(l)/(A)=`cell constant
`(l)/(A)=800xx1.25xx10^(-3)=1`.