If the `E^(@)` for a given reaction has a negative value, then which of the following gives the correct relationship for the of `DeltaG^(@)` and `k_(aq)`?

Options

A. `DeltaG^(@)gt0,K_(eq)lt1`
B. `Delta^(@)gt0,K_(eq)gt1`
C. `DeltaG^(+)lt0,K_(eq)gt1`
D. `DeltaG^(@)lt0,K_(eq)lt1`

Answer

A

Explanation

`ThereforeDeltaG^(@)=-nFE^(@) and DeltaG^(@)=-Rtlog_(e)K_(eq)`