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A solution contains Fe^(2+), Fe^(3+) and...

A solution contains `Fe^(2+), Fe^(3+)` and `T^(-)` ions. This solution was treated with iodine at `35^(@)C. E^(@)` for `Fe^(3+), Fe^(2+)` is `0.77 V` and `E^(@)` for `I_(2)//2I^(-)` = 0.536 V. The favourable redox reaction is:

A

`I^(-)` will oxidised to `I_(2)`

B

`Fe^(2+)` will be oxidised to `Fe^(3+)`

C

`I_(2)` will be reduced to `I^(-)`

D

There will be no redox reaction

Text Solution

Verified by Experts

The correct Answer is:
A
`2(e^(-)+Fe^(+3)toFe^(+2)" "E^(@)=0.77V`
`underline(2I^(-)toI_(2)+2e^(-)" "E^(@)=0.536V" ")`
`2Fe^(+3)+2e^(-)to2Fe^(+2)+I_(2)" "E^(o)=E_(o x)^(o)+E_(red)^(o)`
`=0.77=0.536=0.164V`
So, Reaction will taken place.
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