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The pressure of H(2) required to make th...

The pressure of `H_(2)` required to make the potential of `H_(2)-`electrode zero in pure water at 289K is :

A

`10^(-14)atm`

B

`10^(-12)atm`

C

`10^(-10)atm`

D

`10^(-4)atm`

Text Solution

Verified by Experts

The correct Answer is:
A
`2H^(+)(aq)=2e^(-)toH_(2)(g)`
`thereforeE=E^(0)-(0.0591)/(2)"log"(P_(H_(2)))/([H^(+)]^(2))`
`0=0-0.295"log"(P_(H_(2)))/((10^(-7))^(2))`
`(P_(H_(2)))/((10^(-7))^(2))=1`
`P_(H_(2))=10^(-14)atm`
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