Home
Class 12
CHEMISTRY
The standard EMF of a galvanic cell invo...

The standard `EMF` of a galvanic cell involving cell reaction with `n=2` is found to be `0.295 V` at `25^(@)C` . The equilibrium constant of the reaction would be

A

`2xx10^(11)`

B

`4xx10^(12)`

C

`1xx10^(2)`

D

`1xx10^(10)`

Text Solution

Verified by Experts

The correct Answer is:
D
`E_(cell)^(o)=(2.303RT)/(nF)log" "K_(eq)`
`0.295=(2.303xx8.314xx298)/(2xx96500)log" "K_(eq)`
`log" "K_(eq)=(2xx96500)/(2.303xx3.314xx298)=10`
`K_(eq)="antilog "10=1xx10^(10)`
Promotional Banner

Similar Questions

Explore conceptually related problems

The standard e.m.f of a cell, involving one electron change is found to be 0.591 V at 25^(@) C . The equilibrium constant of the reaction is : (F=96,500C mol^(-1) : R=8.314 Jk^(-1)mol^(-1)

The standard emf of a cell having one electron change is found to be 0.591 V at 25^@ C , The equilibrium constant of the reaction is :

For a cell involving two electron change , E_(cell)^(@) = 0.3 V at 25^(@) C . The equilibrium constant of the reaction is

The standard e.m.f. of a cell, invoving one electron change is found to be 0.591 V at 25^0C . The equilibrium constant of the reaction is ( F= 96500 mol^-1, R=8.314 JK^-1mol^-1)