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The electrode potential E(Zn^(+2)//Zn) ...

The electrode potential `E_(Zn^(+2)//Zn) ` of a zinc electrode or `25^(@)C` with an aqueous solution of `0.1 M ZnSO_(4)` is `[E_((Zn^(+2)//Zn))=-0.76V]["assume"(2.3-3RT)/(F)=0.06at298K]`

A

`+0.73`

B

`-0.79`

C

`-0.82`

D

`-0.70`

Text Solution

Verified by Experts

The correct Answer is:
B
For `Zn^(2+)toZn`
`E_(Zn^(2+)//Zn)=E_(Zn^(2+)//Zn)^(@)-(2.303RT)/(nF)log([Zn])/([Zn^(2+)]))`
`=-0.76-(0.06)/(2)"log"(1)/([(0.1]))=-0.76-0.03`
`E_(Zn^(2+)//Zn)=-0.79V`
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