If `Zn^(2+)//Zn` electrode is diluted 100 times, then the charge in reduction potential is

Options

A. Increase of 59 mV
B. Decrease of 59 mV
C. Increase of 29.5 mV
D. Decrease of 29.5 mV

Answer

A

Explanation

`E_(cell)=(0.059)/(n)log((1)/(C))=-(0.059)/(2)log((1)/(100))`
`=-(0.059)/(2)(-2)=0.059V=59mV`. (increase)