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The voltage of a cell whose half-cells a...

The voltage of a cell whose half-cells are given below is
`Mg^(2+)+2e^(-)rarrMg(s),E^(@)=-2.37V`
`Cu^(2+)+2e^(-)rarrCu(s),E^(@)=+0.34V`
standard EMF of the cell is

Text Solution

Verified by Experts

The correct Answer is:
C
`E_(cell)^(o)=E_("cathode")^(o)-E_("anode"), " "E_(cell)^(o)=0.34-(-2.37)`
`E_(cell)^(o)=2.71V`
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