Home
Class 12
CHEMISTRY
The E^(o) values of the following reduct...

The `E^(o)` values of the following reduction reactions are given
`Fe_((aq))^(3+)+etoFe_((aq))^(2+),E^(o)=0.771V`
`Fe_((aq))^(2+)to2etoFe_((s)),E^(o)=-0.447V`
What will be the free energy change for the reaction
`Fe_((aq))^(3+)+3e^(-)toFe_((s))" "(1F=96485C" mol"^(-1))`

A

`+18.51kJ" "mol^(-1)`

B

`+11.87kJ" "mol^(-1)`

C

`-8.10kJ" "mol^(-1)`

D

`-10.41kJ" "mol^(-1)`

Text Solution

Verified by Experts

The correct Answer is:
B
`DeltaG^(o)=-nFE_(cell)^(o)`
`Fe_((aq))^(3+)+e^(-)toFe_((aq))^(2+),DeltaG_(1)^(o)=-Fxx0.771`
`Fe_((aq))^(2+)+2e^(-)toFe_((s)),DeltaG_(2)^(o)=-2xxFxx(-0.447)`
`=0.894F`
`Fe_((aq))^(3+)+3e^(-)toFe_((s)),DeltaG_(3)^(o)=?`
`DeltaG_(3)^(o)=DeltaG_(1)^(o)+DeltaG_(2)^(o)`
`DeltaG_(3)^(o)=-0.771F+0.894F`
`DeltaG_(3)^(o)=0.123F=0.123xx96485`
`DeltaG_(3)^(o)=11867.6J" "mol^(-1)` or `11.87kJ" "mol^(-1)`.
Promotional Banner

Similar Questions

Explore conceptually related problems

The cell in which the following reaction occurs : 2Fe_(aq)^(3+) + 2I_(aq)^(-) to 2Fe_(aq)^(2+) + I_(2(s)) "has" E_("cell")^(o) = 0.236 V "at" 298 K The equilibrium constnat of the cell reaction is

Calculate the DeltaG^(@) of the following reaction :- Fe^(+2)(aq)+Ag^(+)(aq)toFe^(+2)(aq)+Ag(s) E_(Ag^(+)//Ag)=0.8V" "E_(Fe^(+3)//Fe^(+2))^(0)=0.77V

If the half cell reactions are given as (i) Fe^(2+)(aq)+2e^(-)rarrFe(s),E^(@)=0.44V (ii) 2H^(+)(aq)+ 1//2O_(2)(g)+2e^(-)rarrH_(2)O(l),E^(@)=+1.23V The E^(@) for the reaction.

The standard potential for the reaction, Ag^(+)(aq.)+Fe^(2+)(aq.)toFe^(3+)(aq.)+Ag(s) is 0.028V. What is the standard free energy change for this reaction?

Based on the data given below, the correct order of reducing power is: Fe_((aq.))^(3+) + e rarr Fe_((aq.))^(2+), E^(@) = +0.77 V Al_((aq.))^(3+) + 3e rarr Al_((s)), E^(@) = -1.66 V Br_(2(aq.)) + 2e rarr 2Br_((aq.))^(-), E^(@) = +1.08 V

{:(Given Fe^(+2)+2e^(-)toFe(s),,,,E^(@)=-0.447V),(Fe^(+2)toFe^(+3)+e^(-),,,,E^(@)=-0.771V):} Find E^(@) for the reaction Fe^(+3)+3e^(-)toFe(s)