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Consider the following reaction, Zn(s)...

Consider the following reaction,
`Zn(s)+Cu^(2+) (0.1 M) rarr Zn^(2+) (1 M)+Cu(s)` above reaction, taking place in a cell, `E_("cell")^(@)` is `1.10 V. E_("cell")` for the cell will be `(2.303 (RT)/(F)=0.0591)`

A

2.14 volt

B

1.80 volt

C

1.07 volt

D

0.82 volt

Text Solution

Verified by Experts

The correct Answer is:
C

`E=E^(@)-(0.059)/(n)"log"([Zn^(++)])/([Cu^(++)])=1.10-(0.059)/(2)"log"(1)/(0.1)`
`=1.10-0.0295log10=1.07` volt
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