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The cell Zn | Zn ^(2+) (1M)||Cu ^(2+)(1M...

The cell `Zn | Zn ^(2+) (1M)||Cu ^(2+)(1M)|Cu (E ^(@) _(cell) = 1. 10V)` was allowed to be completely discharged at 298 K. The relative concentration of `Zn ^(2+) ` to `Cu ^(2+) (([Zn ^(2+)])/([Cu^(2+)]))` is :

A

Antilog (24.08)

B

37.3

C

`10^(37.3)`

D

`9.65xx10^(4)`

Text Solution

Verified by Experts

The correct Answer is:
C
`E_(cell)=E_(cell)^(o)-(0.0591)/(n)log" "Q`
where, `Q=([Zn^(2+)])/([Cu^(2+)])`
For complete discharge `E_(cell)=0`
So, `E_(Cell)^(0)=(0.0591)/(2)"log"([Zn^(2+)])/([Cu^(2+)])`
`implies|([Zn^(2+)])/([Cu^(2+)])|=10^(37.3)`
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