Home
Class 12
CHEMISTRY
The reaction: Zn^(2+)(aq)+2e^(-)toZn(s) ...

The reaction: `Zn^(2+)(aq)+2e^(-)toZn`(s) has a electrode potential of -0.76 V. This means-

A

Zn can't replace hydrogen from acids

B

Zn is a reducing agent

C

Zn is an oxidising agent

D

`Zn^(2+)` is a reducing agent

Text Solution

Verified by Experts

The correct Answer is:
B
Since `E_(Zn^(++)//Zn)^(o)` is negative, so Zn has greater tendency to be oxidized. Than hydrogen. Hence it can act as reducing agent.
Promotional Banner

Similar Questions

Explore conceptually related problems

Standard reduction electrode potential of Zn^(2+)//Zn is -0.76V . This means:

The electrode potential, E^(@) , for the reduction of MnO_(4)^(-)" to "Mn^(2+) in acidic medium is +1.51V . Which of the following metal(s) will be oxidised? The reduction reactions and standard electrode potentials for Zn^(2+), Ag^(+) and Au^(+) are given as Zn_((aq))^(2+)+2e^(-)rarrZn_((s)),E^(@)=-0.762V Ag_((aq))^(+)+e^(-)hArr Ag_((x)), E^(@)=+0.80V Au_((aq))^(+)+e^(-)hArr Au_((s)), E^(@)=+1.69V

For a reaction Zn^(+2) + 2e^(-) rarr Zn, E^(@) = -0.76V which of the following statement is true? (E = Electrode potential)