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The standerd potential at 25^(@) for the...

The standerd potential at `25^(@)` for the following Half rection is given :
`Zn^(2+)+2e^(-)toZn,E^(@)=-0.762 V`
`Mg^(2+)+2e^(-)toMg,E^(@)=-2.37 V`
When Zinc dust is added to the solution of `MgCl_(2)`.

A

`ZnCl_(2)` is formed

B

Zinc dissolves in the solution

C

No reaction takes place

D

Mg is precipitated

Text Solution

Verified by Experts

The correct Answer is:
C

this type of reaction does not occur because
`Mg^(2+)E^(o)=-2.37V` while `Zn^(2+)E^(o)=-0.76V`.
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