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The oxidation potential of a hydrogen el...

The oxidation potential of a hydrogen electrode at `pH = 10` and `P_(H_(2)) =1` is

A

0.059V

B

0.59V

C

0.00V

D

0.51V

Text Solution

Verified by Experts

The correct Answer is:
B
`E_(OP)=E_(OP)^(o)-(0.059)/(1)"log"([H^(+)])/(P_(H_(2)))`
`therefore[H^(+)]=10^(-10),P_(H_(2))=1atm,E_(OP)=0.59V`
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