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DeltaG for the reaction : (4)/(3) Al+...

`DeltaG` for the reaction `:`
`(4)/(3) Al+O_(2)rarr (2)/(3)Al_(2)O_(3)`
is `-772 kJ mol^(-1)` of `O_(2)`.
Calculate the minimum `EMF` in volts required to carry out an electrolysis of `Al_(2)O_(3)`

Text Solution

Verified by Experts

`AltoAl^(3+)+3e^(-)`
`(4)/(3)mol" of "Al=(4)/(3)xx3mol" "e^(-)=4mol" "e^(-)`
n=4
`DeltaG=-nFE`
`-772xx1000J=-4xx96500xxE" "thereforeE=(772xx1000)/(4xx96500)=2.0V`
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