The weight of a molecule of the compound`C_(60)H_(122)` is

Options

A. `1.4xx10^(-21) g`
B. `1.09xx10^(-21)g`
C. `5.025xx10^(23) g`
D. `16.023xx10^(23) g`

Answer

A

Explanation

Molecular weight of `C_(60)H_(122)=12xx60+122xx1`
`=720+122=842`
`:' 6xx10^(23)` molecule `C_(60)H_(122)` has mass `=842` gm
`:.` 1 molecule `C_(60)H_(122)` has mass `842/(6xx10^(23))`
`=140.333xx10^(-23) gm = 1.4xx10^(-21)` gm.