Arrange the following in the order of increasing mass (at. Mass of O=16, Cu=63, N=14)
(I) one atom of oxygen (II) one atom of nitrogen
(III) `1xx10^(-10)` mole of oxygen (IV) `1xx10^(-10)` mole of copper

Options

A. `II lt I lt III lt IV`
B. `I lt II lt III lt IV`
C. `III lt II lt IV lt I`
D. `IV lt II lt III lt I`

Answer

A

Explanation

Mass of one atom of oxygen `=16/(6.023xx10^(23))=2.66xx10^(-23)`
Mass of one atom of nitrogen `=14/(6.023xx10^(23))=2.32xx10^(-23)`
Mass of `1xx10^(-10)` mole of oxygen `=16xx10^(-10)`
Mass of `1xx10^(-10)` mole of copper `=63xx1xx10^(-10)`
`=63xx10^(-10)`
So, the order of increasing mass is `II lt I lt III lt IV`.