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1.520 g of the hydroxide of a metal on i...

`1.520 g` of the hydroxide of a metal on ignition gave `0.995 g` of oxide. The equivalent weight of metal is

A

`1.520`

B

`0.995`

C

`19.00`

D

`9.00`

Text Solution

Verified by Experts

The correct Answer is:
D
`("wt, of metal hydroxide")/("wt. of metal oxide")=(EM+EOH^(-))/(EM+EO^(-))`
`=1.520/0.995=(x+17)/(x+8)`
`=1.520x+1.520xx8=0.995x+0.995xx17`
`1.520x+12.160=0.995x+16.915`
or `0.525x=4.755implies x=4.755/0.525=9`.
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