When `22.4 L` of `H_(2)(g)` is mixed with 11.2 of `Cl_(2)(g)`, each at STP, the moles of HCl(g) formed is equal to

Options

A. 0.5 mol of `HCl(g)`
B. 1.5 mol of `HCl (g)`
C. 1 mol of `HCl(g)`
D. 2 mol of `HCl(g)`

Answer

C

Explanation

`{:(,H_(2),+,Cl_(2),rarr,2HCl),("Initial",22.4 L,,11.2 L,,0),("Final",11.2 L,,0,,22.4 L=1" mole"):}`