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The maximum amount of BaSO(4) precipitat...

The maximum amount of `BaSO_(4)` precipitated on mixing `BaCl_(2)` (0.5 M) with `H_(2)SO_(4)` (1M) will correspond to

A

0.5 M

B

1.0 M

C

18 moles

D

100 moles

Text Solution

Verified by Experts

The correct Answer is:
A
`BaCl_(2)+H_(2)SO_(4) rarr BaSO_(4)+2HCl`
One mole of `BaCl_(2)` reacts with one mole of `H_(2)SO_(4)`.
Hence 0.5 mole will react with 0.5 mole of `H_(2)SO_(4)` i.e. `BaCl_(2)` is the limiting reagent.
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