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The number of formula units of calcium f...

The number of formula units of calcium fluoride `CaF_(2)` present in 146.4 g of `CaF_(2)` (The molar mass of `CaF_(2)` is 78.08 g/mol) is

A

`1.129xx10^(24) CaF_(2)`

B

`1.146xx10^(24) CaF_(2)`

C

`7.808xx1-^(24) CaF_(2)`

D

`1.877xx10^(24) CaF_(2)`

Text Solution

Verified by Experts

The correct Answer is:
A
Number of moles of `CaF_(2)=146.4/78.08=1.875`
`:.` No. of formula units `=1.875xxN_(A)`
`=1.875xx6.023xx10^(23)=11.29xx10^(23)=1.129xx10^(24)`
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