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Sodium nitrate on reduction with Zn in p...

Sodium nitrate on reduction with Zn in presence of NaOH solution produces `NH_(3)`. Mass of sodium nitrate nitrate absorbing 1 mole of electron will be

A

`7.750`

B

`10.625`

C

`8.000`

D

`9.875`

Text Solution

Verified by Experts

The correct Answer is:
B
Ammonia is formed by reduction of nitrates and nitrites with Zn and NaOH. Zn and caustic soda produce nascent hydrogen which reacts with nitrates to form ammonia.
`NaNO_(3)+8H^(+)+8e overset(Zn//NaOH)(rarr) NaOH+NH_(3)+2 H_(2)O`
From the equation
Mass of `NaNO_(3)` absorbing 8 moles of electron `=85 g`
`:.` Mass of `NaNO_(3)` absorbing 1 mole of electron `=85/8=10.625 g`.
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