Common salt obtained from sea water contains `95% NaCl` by mass. The appoximate number of molecules present in `10.0g` of the salt is

Options

A. `10^(21)`
B. `10^(22)`
C. `10^(23)`
D. `10^(24)`

Answer

C

Explanation

58.5 g of NaCl contains `6.023xx10^(23)` molecules.
10 g will contain `1.03xx10^(23)` molecules of NaCl.
Since it contain 95 % NaCl, so total number of molecules
`=95/100xx1.03xx10^(23)= 0.98xx10^(23) or 10^(23)`