`KMnO_(4)` reacts with ferrous ammonium sulphate according to the equation `MnO_(4)^(-)+5Fe^(2+)+8H^(+) rarr Mn^(2+)+5Fe^(3+)+4H_(2)O`, here `10 ml` of `0.1 M KMnO_(4)` is equivalent to

Options

A. 20 ml of 0.1 M `FeSO_(4)`
B. 30 ml of 0.1 M `FeSO_(4)`
C. 40 ml of 0.1 M `FeSO_(4)`
D. 50 ml of 0.1 M `FeSO_(4)`

Answer

D

Explanation

`KMnO_(4)=` Mohr salt
`(M_(1)V_(1))/n_(1)=(M_(2)V_(2))/n_(2), (0.1xx10)/1=(M_(2)V_(2))/5, M_(2)V_(2)=5`.