For the reaction `Fe_(2)O_(3)+3CO to 2Fe+3CO_(2)`, the volume of carbon monoxide required to reduce one mole of ferric oxide is

Options

A. `67.2 dm^(2)`
B. `11.2 dm^(2)`
C. `22.4 dm^(3)`
D. `44.8 dm^(3)`

Answer

A

Explanation

`{:(Fe_(2)O_(3),+,3CO,rarr,2Fe,+,3CO_(2)),("1 vol.",,"3 vol.",,"2 vol.",,"3 vol."),("1 mol.",,"3 mol.",,"2 mol.",,"3 mol."):}`
`( :' "vol% = mol%")`
One gram mol of any gas occupies 22.4 litre at NTP. 1 mol of `Fe_(2)O_(3)` requires 3 mol of `CO` for its reduction i.e., 1 mol of `Fe_(2)O_(3)` requires `3xx22.4` litre or `67.2 dm^(3) CO` to get itself reduced.