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Assertion : In a reaction Zn((s))+CuSO(4...

Assertion : In a reaction `Zn_((s))+CuSO_(4 (aq)) rarr ZnSO_(4(aq))+Cu_((s)), Zn` is a reductant but itself get oxidized.
Reason : In a redox reaction, oxidant is reduced by accepting electrons and reductant is oxidized by losing electrons.

A

If both assertion and reason are true and the reason is the correct explanation of the assertion.

B

If both assertion and reason are true but reason is not the correct explanation of the assertion.

C

If assertion is true but reason is false.

D

If the assertion and reason both are false.

Text Solution

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The correct Answer is:
To analyze the assertion and reason provided in the question, we will break it down step by step. ### Step 1: Understanding the Reaction The reaction given is: \[ \text{Zn}_{(s)} + \text{CuSO}_{4(aq)} \rightarrow \text{ZnSO}_{4(aq)} + \text{Cu}_{(s)} \] In this reaction, solid zinc (Zn) reacts with copper sulfate (CuSO₄) in aqueous solution to produce zinc sulfate (ZnSO₄) and solid copper (Cu). **Hint**: Identify the reactants and products in the reaction to understand what is happening. ### Step 2: Identifying Oxidation States - In the reactants: - Zinc (Zn) is in the elemental state, so its oxidation state is 0. - Copper in copper sulfate (CuSO₄) has an oxidation state of +2. - In the products: - Zinc in zinc sulfate (ZnSO₄) has an oxidation state of +2. - Copper (Cu) in the elemental state has an oxidation state of 0. **Hint**: Determine the oxidation states of the elements involved to see how they change during the reaction. ### Step 3: Determining Oxidation and Reduction - Zinc (Zn) goes from an oxidation state of 0 to +2, which means it loses electrons and is oxidized. - Copper (Cu) goes from an oxidation state of +2 to 0, which means it gains electrons and is reduced. **Hint**: Remember that oxidation involves the loss of electrons, while reduction involves the gain of electrons. ### Step 4: Identifying the Reductant and Oxidant - Zinc (Zn) is the reductant (reducing agent) because it donates electrons to copper ions (Cu²⁺). - Copper ions (Cu²⁺) are the oxidant (oxidizing agent) because they accept electrons from zinc. **Hint**: The substance that is oxidized is the reductant, and the substance that is reduced is the oxidant. ### Step 5: Evaluating the Assertion and Reason - **Assertion**: "In the reaction, Zn is a reductant but itself gets oxidized." This is true because Zn donates electrons and is oxidized. - **Reason**: "In a redox reaction, oxidant is reduced by accepting electrons and reductant is oxidized by losing electrons." This is also true and correctly explains the assertion. **Hint**: Assess whether both statements are true and if the reason supports the assertion. ### Conclusion Both the assertion and the reason are true, and the reason correctly explains the assertion. Therefore, the correct answer is: **Both assertion and reason are true, and the reason is the correct explanation of the assertion.** ### Final Answer Both assertion and reason are true, and the reason is the correct explanation of the assertion.

To analyze the assertion and reason provided in the question, we will break it down step by step. ### Step 1: Understanding the Reaction The reaction given is: \[ \text{Zn}_{(s)} + \text{CuSO}_{4(aq)} \rightarrow \text{ZnSO}_{4(aq)} + \text{Cu}_{(s)} \] In this reaction, solid zinc (Zn) reacts with copper sulfate (CuSO₄) in aqueous solution to produce zinc sulfate (ZnSO₄) and solid copper (Cu). ...
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Oxidation and reduction process involves the transaction of electrons. Loss of electrons is oxidation and the gain of electrons is reduction. It is thus obvious that in a redox reaction, the oxidant is reduced by accepting the electrons and the reductant is oxidised by losing electrons. The reactions in which a species disproportionates into two oxidation states (lower and higher) are called disproportionation reactions. In electrochemical cells, redox reaction is involved, i.e., oxidation takes place at anode and reduction at cathode. Which of the following reactions is/are correctly indicated?

Oxidation and reduction process involves the transaction of electrons. Loss of electrons is oxidation and the gain of electrons is reduction. It is thus obvious that in a redox reaction, the oxidant is reduced by accepting the electrons and the reductant is oxidised by losing electrons. The reactions in which a species disproportionates into two oxidation states (lower and higher) are called disproportionation reactions. In electrochemical cells, redox reaction is involved, i.e., oxidation takes place at anode and reduction at cathode. The reaction Cl_(2)to Cl^(-)+ClO_(3)^(-) is:

Oxidation and reduction process involves the transaction of electrons. Loss of electrons is oxidation and the gain of electrons is reduction. It is thus obvious that in a redox reaction, the oxidant is reduced by accepting the electrons and the reductant is oxidised by losing electrons. The reactions in which a species disproportionates into two oxidation states (lower and higher) are called disproportionation reactions. In electrochemical cells, redox reaction is involved, i.e., oxidation takes place at anode and reduction at cathode. Select the correct statement:

Oxidation and reduction process involves the transaction of electrons. Loss of electrons is oxidation and the gain of electrons is reduction. It is thus obvious that in a redox reaction, the oxidant is reduced by accepting the electrons and the reductant is oxidised by losing electrons. The reactions in which a species disproportionates into two oxidation states (lower and higher) are called disproportionation reactions. In electrochemical cells, redox reaction is involved, i.e., oxidation takes place at anode and reduction at cathode. Detennine the change in oxidation number of sulphur in H_(2)S and SO_(2) respectively in the following reaction: 2H_(2)S+SO_(2) to 2H_(2)O+3S

Oxidation and reduction process involves the transaction of electrons. Loss of electrons is oxidation and the gain of electrons is reduction. It is thus obvious that in a redox reaction, the oxidant is reduced by accepting the electrons and the reductant is oxidised by losing electrons. The reactions in which a species disproportionates into two oxidation states (lower and higher) are called disproportionation reactions. In electrochemical cells, redox reaction is involved, i.e., oxidation takes place at anode and reduction at cathode. In the reaction: I_(2)+2S_(2)O_(3)^(2-) to 2I^(-)+S_(4)O_(6)^(2-)

CuSO_(4)(aq.)+Zn(s) to ZnSO_(4)+Cu uarr

ERRORLESS -SOME BASIC CONCEPTS OF CHEMISTRY-Ordinary Thinking (Objective Questions) Oxidation, Reduction, Oxidizing and Reducing agent
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