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When KMnO(4) is reduced with oxalic acid...

When `KMnO_(4)` is reduced with oxalic acid in acidic solution, the oxidation number of `Mn` changes from

A

7 to 4

B

6 to 4

C

7 to 2

D

4 to 2

Text Solution

Verified by Experts

The correct Answer is:
C
`{:(" COOH"),(5" | " +2 Koverset(+7)(M)nO_(4)+3H_(2)SO_(4) rarr K_(2)SO_(4)+2 overset(+2)(M)nSO_(4)+10 CO_(2) +8 H_(2)O),(" COOH"):}`
In this reaction oxidation state of Mn change from +7 to +2.
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